Question

Someone want to check my work on this DE?

Answer 1

I think that everything is ok but am unsure

Answer 2

\[{dy \over dx} = {\sqrt{x^2 + y^2} - x \over y}\] is the original equation

Answer 3

how did you go from y= ux
to the other part.
dy= x du + u dx

Answer 4

thats the differential using the chain rule

Answer 5

nevermind I see it

Answer 6

Ima do it really fast see if it works out.

Answer 7

seems right.

Answer 8

It's been a while :P

Answer 9

After you ingetrate and you e^ everything does e^c become an arbitary constant where we can set it to be 1?

Answer 10

Well c is an arbitary constant so e^c is too. Not sure what you mean about setting it to 1

Answer 11

Yeah don't take my word for it usually when there is an arbitary constant like that I usually set it to 1. I should really ask why haha. But you did everything right.

Answer 12

Thanks much. I don't see any mistakes but knowing myself well I never assume that there aren't any