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Which of the following shows the square completed in this equation? x2 + 3x - 5 = 0 I dont get how to do this one.
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which of the following?
it should look something like \[(x+\frac{3}{2})^2=\text{something}\]
\[x^2+3x-5=0\] \[x^2+3x=5\] \[(x+\frac{3}{2})^2=5+\frac{9}{4}=\frac{29}{4}\] \[x+\frac{3}{2}=\pm\frac{\sqrt{29}}{2}\] \[x=-\frac{3}{2}\pm\frac{\sqrt{29}}{2}\]
thanks! but which one wuld it be? (x + 9)2 = 14 (x - 3)2 = 8 (x + 1.5)2 = 7.25
Did you see that Satellite said the left side should be (x+3/2)^2
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Yes. so it would be the 2nd one? sorry just confused
It's the third one. You get there after this stage: (x+3/2)^2=5+9/4 3/2 is 1.5 and 5+9/4 is 7.5
thanks!
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