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Prove That : ___________ SinA/2=sqrt{(c-b)/2c}
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?? what are b and c??
variables :D
look i will tell u where i stopped at :D.. I began with the L.H.S :SinA/2 and then i worked on the law sqrt{(1-cosA)/2}
use the relation:\[\sin(A/2)=\frac{1-\cos(A)}{2}\]
and at the substitution I faced the problem
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sorry that should be \[\sin^2(A/2)=...\]
no thats right @asnaseer
|dw:1335650315768:dw|
is it a right angled triangle??
now use this for the right-angled triangle I drew above:\[\sin^2(A/2)=\frac{1-\cos(A)}{2}\]
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Its right angled triangle at C ,
|dw:1335650434860:dw|
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