Question

What is the slope of the tangent line of y= (e^(-x))/(x+1) at x=1

Answer 1

you need to find derivative

y' = (x+1)*-e^(-x) - (e^(-1)
--------------------
(x+1)^2
at x = 1

y' = 2*-e^-1 - (e^-1)
--------------
4

= e^(-1) / 4 = 0.092

slope of tangent = 0.092

Answer 2

my maths is rubbish today - i made an error in last line
y' = -3e^-1 / 4

Answer 3

i get that = -1.1036

Answer 4

divided by 4
which is -0.2759