Find the fifth term and the nth term of the geometric sequence whose initial term, a, and common ratio, r, are given.

a = √ 5 ; r = √ 5

answers:

a5=5√ 5 ; 5^n/2

a5=25√ 5 ; 5^n/2

a5=5√ 5 ; 5^n-1

a5=25√ 5 ; 5^n

Question

Find the fifth term and the nth term of the geometric sequence whose initial term, a, and common ratio, r, are given.

a = √ 5 ; r = √ 5 

answers: 
		
a5=5√ 5  ; 5^n/2
		
a5=25√ 5  ; 5^n/2
		
a5=5√ 5  ; 5^n-1
		
a5=25√ 5  ; 5^n

campbell_st · Answer

a term in a geometric series is found usng

$$T _{n}=a \times r^{n-1}$$

in your question you have a and r and n = 5

substitute and evaluate

anonymous · Answer

$$a_1=\sqrt{5}, a_2=\sqrt{5}\times \sqrt{5}=5,a_3=5\sqrt{5}, a_4=25,a_5=25\sqrt{5}...$$

anonymous · Answer

the answer es 25√5 but wich one is the nth term?????

anonymous · Answer

nth term is $\sqrt{5}\times \sqrt{5}^{n-1}=\sqrt{5}^n=5^{\frac{n}{2}}$

anonymous · Answer

5^(5/2)

anonymous · Answer

yes, that one

anonymous · Answer

thank u

anonymous · Answer

yw ( you did it before i did)

campbell_st · Answer

then go back to the formula and replace use n... where you used 5