Find the sum.
Equation is inserted as a comment:)

Question

Find the sum.
Equation is inserted as a comment:)

anonymous · Answer

no its not

anonymous · Answer

$$\sum_{k=1}^{\infty}6(1/5)^(k-1)$$

anonymous · Answer

you're in complicated math like me!

anonymous · Answer

lol:)

anonymous · Answer

can't really help though. i'm a little lost when it comes to this stuff too. haha

experimentx · Answer

you really sure k=1??

anonymous · Answer

yes, it gives that to me.

experimentx · Answer

$$ \sum_{k=1}^{n} \frac{6(k-1)}{5}$$
is this the question??

experimentx · Answer

If that is the question then,
6/5 (0+1+2+3+ ... +(n-1))

zarkon · Answer

$$\sum_{k=1}^{n} 6\left(\frac{1}{5}\right)^{k-1}$$

turingtest · Answer

really? I don't see it...

anonymous · Answer

rewrite your question. everyone's confused. lol

turingtest · Answer

I'm going to assume Zarkon is right as usual and try to figure our how he turned this into a geometric series

turingtest · Answer

oh I was confused, he just rewrote it

turingtest · Answer

...it was typed poorly befor

zarkon · Answer

I guess it goes up to infinity

$$\sum_{k=1}^{\infty} 6\left(\frac{1}{5}\right)^{k-1}$$

turingtest · Answer

aren't there formulas for geometric series up through n ? or only for infinite Geom series?

zarkon · Answer

there is

turingtest · Answer

wikiw time I guess lol

zarkon · Answer

a formula for finite geometric sums that is

turingtest · Answer