Question

Suppose Q = x^{2} y^{3} . If \frac{dQ}{dt} = -2 and \frac{dx}{dt} = -1, find \frac{dy}{dt} when x = 3 and y = 2 .

\frac{dy}{dt} =

Answer 1

i tried so many times and i got 1/3 but this doesnt seem to be correct

Answer 2

Suppose \( Q = x^{2} y^{3}\) . If \( \frac{dQ}{dt} = -2 \) and \( \frac{dx}{dt} = -1 \), find \( \frac{dy}{dt} \) when x = 3 and y = 2 .\( \frac{dy}{dt} \) =

Answer 3

4/27 ?

Answer 4

@ acekly not correct

Answer 5

\( \frac{dQ}{dt} = 2x y^3\;dx/dt + x^23y^2\;dy/dt \) , put the given values ....

Answer 6

5/54?

Answer 7

@ acekly not correct

Answer 8

@experimentX Yep, I got -50/108 from that, I think, but I may have commited a mistake somewhere...my brain must be malfunctioning.

Answer 9

i got 54/23

Answer 10

not correct either

Answer 11

@bmp don't worry i haven't slept all night

Answer 12

ok its 23/54 for the answer

Answer 13

i got it, thanks guys !

Answer 14

23/54?

Answer 15

alryte

Answer 16

http://www.wolframalpha.com/input/?i=-2+%3D+2*3*2^3*-1+%2B+3^2*3*2^2*x