the number N, in millions, of hearing impaired individuals of age x can be approximated by N=-0.00006x^3+0.006x^2-0.1x+1.5. Approximate to the nearest million the number of hearing impaired individuals of age 25 and 45
Have you tried to calculate the answers?
no looking at my notes it is a scientific notation but thats all I know
Can you try calculating the first term (-0.00006x^3) by sustituting 25 for x?
0.9375
or 0.938
\[-0.00006x ^{3}=-(6\times 10^{-5})\times x ^{3}\] \[-(6\times 10^{-5})\times 25^{3}=-0.9375\]
Ok I got a final answer of 3.69 .....would the nearest million be 4?
wait the first number is neg so Im wrong
The second term can be written as: \[6\times10^{-3}\times x ^{3}\] Can you substitute 25 for x and calculate?
3.75
Good work. So the calculation for age 25 years is: -0.9375 + 3.75 -2.5 + 1.5
1.8125
would I round it to 2 million?
or 1.81
Gr8! Yes, you are required to round to 2 million. Do you want to try for age 45 and post back the answer for me to check?
awesome THANK YOU!!!! Sure give me a couple mins
15 million?
Check against my result for each term as follows: -5.4675 + 12.15 - 4.5 + 1.5
yes that what I got answer 14.6175
Did you get all the signs right? I get 3.6825 million which rounds to 4 million.
I recalculated and got the same, I supose I hit the wrong sign somewhere
same as in 3.6825
Wonderful. Thanks for perservering :)
Auh THANK YOU for walking me through it!! Your a life saver :). This is my last class to get my associates degree and I am HORRIBLE with math
Good luck with your studies. I had to work very hard to get my math grades up so I know how you feel
thanks
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