Question

f(x)=sin(6x+2)
f'(x)=?

I'm supposed to be using the chain rule, and with that I have:

(cos(x))(6x+2)(6)

Help please!

Answer 1

no, its 6cos(6x+2)

Answer 2

\[f'(x) = \cos(6x+2)\cdot {d \over dx} (6x+2)=6\cos(6x+2)\]

Answer 3

f(x)=sin(x)
f'(x)=cos(x) * x'

Answer 4

this is just the chain rule, take derivative of the outside function and leave the inside the same, then multiply by the derivative of the inside function

Answer 5

\[d/dx(\sin(6 x+2)) = 6 \cos(6 x+2)\]

Answer 6

the same thing happens when we take the derivative of x^2, its really 2(x)(1) we just dont write the 1

Answer 7

So then f(x)=sin(x^4)
f'(x)=cos(4x^3)(x^4)

Answer 8

\[f'(x)=\cos(x^4)4x^3\]

Answer 9

no dont take the derivative on the inside
ccos(x^4)(4x^3)

Answer 10

leave the inside the same, just ike we leave the x alone in x^2

Answer 11

Awesome thanks you wonderful people

Answer 12

yw