Question

A mass attached to a vertical string has position function given s(t)=3sin(2t) where t is measured in seconds and s in inches.

Find the velocity at time t=3
Find the acceleration at time t=3

I have the velocity at time t=3 at 6cos(6)
I don't know how to find the acceleration

Answer 1

CRACK IT SEE U R BOOK FIRST AND IF U WANT MORE help! IN UNDERSTANDING I'M HERE
TO HELP U!!

Answer 2

You know calculus right?

Answer 3

I'm just taking calculus 1 right now..

Answer 4

do the same things for 6cos(3x)

Answer 5

Acceleration= (final velosity- initial velocity)/ time

your velocity is your acceleration JUST SQUARE IT IF IT IS _M/S
ONLY

Answer 6

you got the velocity wrong

Answer 7

s(t)=3sin(2t)
chain rule should get
s'(t)=v(t)=6cos(2t)

Answer 8

derive it once more with the chain rule to get the accleration.

Answer 9

btw, the derivative of cos(t) is -sin(t)

Answer 10

d(6cos(2x))/dx = -12sin(2x)

Answer 11

d/dx f(g(x)=f'(g(x))g'(x)

Answer 12

@zzr0ck3r , you do realize we're here to teach him, not give him the answer, right?

Answer 13

no i didnt actually, ive been here for one day. people just post answers, and i said do what he did again...sorry i guess?

Answer 14

Yes, this place is supposd to be for teaching, but people usually just give the answers for medals.

Answer 15

We're supposed to report people that "answer snipe" (give the answer when others are helping one work through), but to me it's a little harsh

Answer 16

I usually just go FUU and move on.

Answer 17

ahh , im still learning this place. makes since

Answer 18

ty for info

Answer 19

@inkyvoyd how did I get velocity wrong? I got the derivative of the equation using the chain rule, and then substituted the time that they gave me? All I was looking for was how to get the acceleration

Answer 20

d/dx f(g(x)=f'(g(x))g'(x)

Answer 21

the velocity is right, he might not understand that you pluged in x=3

Answer 22

f(x)=sin(g(x))

Answer 23

@jmacar89 , yes, you got it right, careless error on my part.

Answer 24

the second derivative is the acceleration, however

Answer 25

Alright, thanks!

Answer 26

do the same thing you did to get the velocity from the position function, but this time start with the velocity function