Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.040(assume the density of water to be one).
Mole fraction = 0.04/1 = 1/25. In 25 moles of the total mixture, 1 mole of ethanol and 24 moles of water are present. 24 moles of water weigh 24 x 18 = 432 g = 432 mL (18g is the molar mass of water) 1 mole of ethanol is present in 432 mL of water. Molarity is no. of moles of solute present in 1 L of solution. So molarity = 1 x 1000 / 432 = 1000/432 = 2.315 M (approx.)
but wont ethanol also occupy sum volume?
wait
*whistling*
whats the answer?
idk meritnation says ur correct they used the same method
molarity M= (WB/WA)*1000/V mole fraction of C2H5OH= 0.040 molar wt. of ethanol= 46gm wt. of ethanol in 1 mole of soln= 46*0.04=1.84 mole fraction of water= 0.960 molar wt. of water= 18gm wt. of water in 1 mole of solution=17.28 Volume of solution= 1.84+17.28= 19.12ml (1gm=1ml) therefore, M= (1.84/17.28)*1000/0.01921 =0.00556 M
is that...??
wth i cant copy but meritnations answer matches ur first
Quote: "therefore, M= (1.84/17.28)*1000/0.01921 =0.00556 M" I'm afraid this is wrong. Answer is [ethanol] ≈ 0.002 mol/L
?plz xplain
hmmmm...
Instead of using formulae, I prefer working out on an numerical example. I start with 1.00 mole of mixture. What is its composition in moles? ethanol = ........ mol water = .........mol. then for each substance, work out the mass: ethanol = ........... g water = ............ g then volume (assume density of ethanol is similar to that of water, or use the actual value of 0.79): ethanol = ............. mL water = .............. mL Final volume (ignore the slight contraction that appears when you mix ethanol and water): Final volume = .............. mL Finally: [ethanol] = ................. mol/L
@shruti : sorry, I realise now I typed the same answer as yours! Only your last line was not correst, but everything else was ok!
i dont get it how can i do the first blank it contains 1 mole ethanol and how many moles of water?
By definition "mole fraction of ethanol is 0.040" means there is 0.040 mole of ethanol in 1.000 mole of mixture.
i dont think we can assume density of eth and water to be the same. and density of ethanol would have been provided if needed...
If ethanol's density is not provided, it means you have to approximate the final volume. There are 2 ways out: - ignore the volume of ethanol completely and the answer is 0.00222 - equate density of eth. and water and answer is 0.00209 Using d = 0.79 yields 0.00204 Real answer is between 0.00204 and 0.00209
its okay vincent.
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