In large televisions, electrons are accelerated from rest by a potential difference of 20 kV and shot onto a phosphorescent screen to produce an image. What is the speed of the electrons when they reach the screen?

Question

anonymous · Answer

$$v=\sqrt{(2eV/m)}$$

anonymous · Answer

what is the value of e and v and m ???

anonymous · Answer

flutter

anonymous · Answer

When you accelerate the electron with charge e=1.6x10^-19 C through a potential difference of V, it gains a Kinetic energy of eV.
As you can see, simple conservation of energy.
eV=1/2mv^2

anonymous · Answer

e=1.6 x 10^-19 C
m=9.1x10^-31 kg
V=2x10^4 V