Question

Prove Trig

Answer 1

write down tan as sin/cos and cot as cos/sin..
u will get the answer after simplification

Answer 2

Tried that, ended up in a big mess

Answer 3

\[\frac{\cos \theta}{1- \frac{\sin \theta}{\cos \theta}}+\frac{\sin \theta}{1-\frac{\cos \theta}{\sin \theta}}\]multiply first one by cos theta
and second one by sin theta\[\frac{\cos^2 \theta}{\cos \theta-\sin \theta}+\frac{\sin^2 \theta}{\sin \theta-\cos \theta}\]\[=\frac{\sin^2 \theta-\cos^2 \theta}{\sin \theta-\cos \theta}\]\[=\frac{(\sin \theta-\cos \theta)(\sin \theta+\cos \theta)}{\sin \theta -\cos \theta}\]now sin theta-cos theta cancels\[=\frac{\cancel{(\sin \theta-\cos \theta)}(\sin \theta+\cos \theta)}{\cancel{\sin \theta-\cos \theta}}\]

Answer 4

Arnab09 is right - where did you get stuck? - ok lalay has proved it for you...

Answer 5

I got stuck at the sin(theta) - cos(theta). Forgot you can flip that to equal the other denominator.