Question

A straight wire of length 3.5 m carries a current of 42 A and it is placed on a horizontal table in a horizontal uniform magnetic field. The wire makes an angle of 44° with the magnetic field lines. If the magnitude of the force on the wire is 9.0 N, what is the magnitude of the magnetic field?
0.23 T
0.14 T
0.088 T
0.021 T
0.067 T

Answer 1

Use this formula
\[F = BILsin(\theta)\]
where
L-->Length of wire of length
I--> Current (in A)
B-->Magnetic Field (in T)
F--> Force
theta -->angle between wire and magnetic field

Answer 2

Now try and get the answer

Answer 3

thanx i will solve directly

Answer 4

it will be 0.088 T if any one the the question and want the answer :D

Answer 5

You are right