Question

A 30.0 Picture C charged particle moves along the x-axis with a speed of 30.0 m/s. It enters a magnetic field given by Picture . Determine the magnitude of the magnetic force on the particle.
6.34 × 10-4 N
5.25 × 10-4 N
1.72 × 10-4 N
4.69 × 10-4 N
2.31 × 10-4 N

Answer 1

@shivam_bhalla do u have eqution for these

Answer 2

Picture please??

Answer 3

there was no picture

Answer 4

I think you should have a relook at your question :D

Answer 5

;) ok wait :D

Answer 6

Anyways, I will give you the formula governing this . It is
\[F= q* (v \times B)\]
\[F= qvBsin(\theta)\]
F-->force
v-->Velocity of charge
B-->magnetic field
theta-->angle between charge and magnetic field

Answer 7

Now we need the picture for angle between charge and magnetic field

Answer 8

ok

Answer 9

these is the question

Answer 10

Oh. You missed the vectors. In that case you should find cross product between velocity and magnetic field vector
The velocity vector is indirectly mentioned in the question
v = 30 i
B = 0.5 y + 0.3 z
Now find v x B cross product

Answer 11

B=\[\sqrt{.5^2+.3^2}=\sqrt{34}/10\]

v= \[\sqrt{30}\]

\[v*b =3.1\]

\[F=q*v*B =6\sqrt{255}\]

Answer 12

@shivam_bhalla what is wrong with my calculation

Answer 13

Nope.

Do you know how to take cross product of 2 vectors??

Answer 14

:\ unfortiontly no :(

Answer 15

Ok. I will teach you.

Do you know what are vectors?? If Yes, do you know about i,j,k unit vector??

Answer 16

yes i know abit about it

Answer 17

Ok. then it makes my job easier. Also do you know about determinants(maths)??

Answer 18

what it mean ? :)

Answer 19

OK. Forget it. Let me teach you.

Cross product is denoted by " x "
Some basic cross product

i,j,k are unit vectors along x , y and z axis respectively, then
i x j = k
j x k = i
k x i = j

Set 2 ::

j x i = - k
k x j= - i
i x k= - j

Hope you got that

Answer 20

got it

Answer 21

what else ?

Answer 22

Ok. Now
For
vector A nad B given by

A = a i + b j + ck
B = p i + q j + r k

Can you find A x B expression?

Answer 23

*and

Answer 24

u forget to tell me i*i or j*j
i think it will be 0

Answer 25

Bingo and yes they will be zero. Forgot to mention that. Sorry :)

Answer 26

Two points
1) It is not i*i. It is i x i (pronunced as "i cross i")
2)k x k =0 too

Answer 27

ok
i can solve now or there are any thing else

Answer 28

OK
\[F= q* (v \times B)\]
v = 30 i
B = 0.5 y + 0.3 z
Now find v x B cross product

Then Find F. You will get in terms of i ,j and k
Let
the final answer F be
F = a i + b j + ck
Then magnitude of F = sqrt(a^2 + b^2 + c^2)

Answer 29

I am going out. Will be back in 15 minutes.

Answer 30

I am back. Got the answer @laura115

Answer 31

yes 5.25 × 10-4 N Wb :D

Answer 32

OK great :D

Answer 33

Well done :D

Answer 34

:D thanx but u teach very good :D :D