Question

A charged particle of mass 'm' and having a charge 'Q' is placed in an electric field E which varies with time as E = E' sin (wt) ----(w=omega)
what is the amplitude of SHM executed by the particle?
a) QE'^2/mw^2
b)Q E'/mw^2
c)sqrt(QE'/mw^2)
d)QE'/mw

Answer 1

What is the general equation for a SHM @goutham1995 ??

Answer 2

X = a sin(wt + theta)

Answer 3

@goutham1995 , It should be logically option B .The simple approach should be

Let
\[\large x= \frac{QE'}{m {\omega}^2}\]
\[\large m {\omega}^2x=QE'\]
It is of the form
\[\large m(a)= F\]
a = -w^2x
F = qE'

Answer 4

Rest of options won't give this. :) So only option B is correct

Answer 5

@goutham1995

Answer 6

but how do you do it without taking those options?