Evaluate the integral
\[\int\limits_{2}^{4}(3x^{-2}-6)dx\]
\[\int\limits{ax^b}dx = \frac{ax^{b+1}}{b+1}\]
also
\[\int\limits_{a}^{b}f(x) dx=\int\limits_{}^{}f(b)dx-\int\limits_{}^{}f(a)dx\]
^ is fundamental theorem of calculus.
that's not the fundamental theorem of calculus
No, I typed it wrong, didn't I?
the fundamental theorem of calculus is\[\frac d{dx}\int_a^b f(t)dt=f(b)b'-f(a)a'\]
it's "fundamental" because it relates the idea of the derivative and integral as inverses of each other
so what is the answer I got -3/4 but I am not sure that its correct.
I guess I shoud have made that partial wrt x on a and b above to cover all bases, but whatever
\[\frac d{dx}\int_a^x f(t)dt=f(x)~~~~\text{where a is a constant}\]is another way it's stated, but really that's a limited case
@TuringTest , my 80's textbook disagrees with you, So i'm going to have to say I win this one.
so what is the answer I got -3/4 but I am not sure if that is correct.
@inkyvoyd if that is exactly what you book says then it is wrong.
@Zarkon , I doubt my book actually says this, but I like to disagree just to disagree.
that is part of the corollary statement if I remember correctly and fyi, disagreeing with Zarkon is usually a bad idea
It says, there are two fundamental theorems of integral calculus
I think inky's right.
The first is what I said.
The second is what you said.
even my textbook agrees with inky's
\[\int_{a}^{b}f(x)dx=F(b)-F(a)\]
The corollary of your theorem, the second one, is that if y=f(x) is contiuous, there exists a integral blah blah blah
where \[F'(x)=f(x)\]
ohh yeah, Zarkon's right again. :facepalm:
@Zarkon , my bad. There's a difference between what I said and what you said.
What you said is what your textbook says.
What I said is what my hedgehog says.
*what my textbook says.
But, my hedgehog says something else.
He meant antiderivative, not indefinite integral.
Hey, good enough. I never took trig xD
But my hedgehog evidently did.
@tburn I don't think this is correct. I got \( -\frac{45}{4}\) What did you get for the antiderivative?
\[-3/1x^{-1}-x\]
It should be: \( -\frac{3}{x} - 6x\) Maybe check your exponentiation?
Okay, thanks
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