Question

given the following revenue and cost functions, find the x-value that makes profit a maximum:
R(x)=57x-2x^2
C(x)=21x+106
(remember that profit equals revenue minus cost)

Answer 1

First step: Subtract the cost function from the revenue function to give a profit function. Then find the maximum of the profit function.

Answer 2

would it look like this: (f(x)=57x-2x^2)-(f(x)=21x+106)

Answer 3

\(R(x)=57x-2x^2\)
\(C(x)=21x+106\)
\(P(x)=R(x)-C(x)\)
\(P(x)=57x-2x^2-(21x + 106)\)
\(P(x)=-2x^2+36x-106\)

Answer 4

k, give me a minute to digest...

Answer 5

so then P(9)=54?

Answer 6

P(9)=56, and 9 is the correct answer, yes.

Answer 7

thank you.