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Mathematics 14 Online
OpenStudy (anonymous):

lcm x^2+9x, x^2-9x

OpenStudy (asnaseer):

first factorise each expression

OpenStudy (anonymous):

ok

OpenStudy (asnaseer):

what do you get?

OpenStudy (anonymous):

x(x+9) x^2+9x

OpenStudy (asnaseer):

you have factorised the first expression correctly, now also factorise the second expression please

OpenStudy (anonymous):

x(x-9)

OpenStudy (asnaseer):

ok, so now you need to find the lcm of x(x+9) and x(x-9)

OpenStudy (asnaseer):

you should notice that both expressions have x as a common factor

OpenStudy (anonymous):

yes

OpenStudy (asnaseer):

one way to work out the lcm is as follows: lcm(a,b) = (a*b)/gcd(a,b) where gcd is the greatest common divisor, which in this case is 'x'

OpenStudy (anonymous):

so my lcm is x?

OpenStudy (asnaseer):

no

OpenStudy (asnaseer):

the gcd in this case is 'x'

OpenStudy (anonymous):

i know but im trying to find the lcm

OpenStudy (asnaseer):

lcm(a,b) = (a*b)/gcd(a,b)

OpenStudy (asnaseer):

you know a, b and the gcd

OpenStudy (mertsj):

Very simple. Take the largest power of every DIFFERENT factor

OpenStudy (mertsj):

You have three different factors and each is to the first power so take the first power of every different factor and there's your LCM

OpenStudy (anonymous):

so it would be 2?

OpenStudy (asnaseer):

no

OpenStudy (anonymous):

cuz its a power of 2

OpenStudy (asnaseer):

lcm( x(x+9), x(x-9) ) = x(x+9) * x(x-9) / x

OpenStudy (anonymous):

o i c

OpenStudy (mertsj):

LCM = x(x-9)(x+9)

OpenStudy (anonymous):

thank u

OpenStudy (mertsj):

yw

OpenStudy (mertsj):

Largest Power of Every Different Factor Different factors are x, x+9, x-9 Each is to the first power So largest power of every different factor is x(x-9)(x+9) Works every time.

OpenStudy (asnaseer):

as does: lcm(a,b) = (a*b)/gcd(a,b)

OpenStudy (mertsj):

Absolutely however more complicated.

OpenStudy (asnaseer):

really?

OpenStudy (mertsj):

Maybe it's whatever one is used to. We'll let the asker decide which he/she wishes to use.

OpenStudy (mertsj):

Choice is good.

OpenStudy (asnaseer):

agreed :)

OpenStudy (anonymous):

thanks guys :)

OpenStudy (mertsj):

yw

OpenStudy (asnaseer):

yw

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