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OpenStudy (asnaseer):
first factorise each expression
OpenStudy (anonymous):
ok
OpenStudy (asnaseer):
what do you get?
OpenStudy (anonymous):
x(x+9) x^2+9x
OpenStudy (asnaseer):
you have factorised the first expression correctly, now also factorise the second expression please
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OpenStudy (anonymous):
x(x-9)
OpenStudy (asnaseer):
ok, so now you need to find the lcm of x(x+9) and x(x-9)
OpenStudy (asnaseer):
you should notice that both expressions have x as a common factor
OpenStudy (anonymous):
yes
OpenStudy (asnaseer):
one way to work out the lcm is as follows:
lcm(a,b) = (a*b)/gcd(a,b)
where gcd is the greatest common divisor, which in this case is 'x'
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OpenStudy (anonymous):
so my lcm is x?
OpenStudy (asnaseer):
no
OpenStudy (asnaseer):
the gcd in this case is 'x'
OpenStudy (anonymous):
i know but im trying to find the lcm
OpenStudy (asnaseer):
lcm(a,b) = (a*b)/gcd(a,b)
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OpenStudy (asnaseer):
you know a, b and the gcd
OpenStudy (mertsj):
Very simple. Take the largest power of every DIFFERENT factor
OpenStudy (mertsj):
You have three different factors and each is to the first power so take the first power of every different factor and there's your LCM
OpenStudy (anonymous):
so it would be 2?
OpenStudy (asnaseer):
no
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OpenStudy (anonymous):
cuz its a power of 2
OpenStudy (asnaseer):
lcm( x(x+9), x(x-9) ) = x(x+9) * x(x-9) / x
OpenStudy (anonymous):
o i c
OpenStudy (mertsj):
LCM = x(x-9)(x+9)
OpenStudy (anonymous):
thank u
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OpenStudy (mertsj):
yw
OpenStudy (mertsj):
Largest Power of Every Different Factor
Different factors are x, x+9, x-9
Each is to the first power
So largest power of every different factor is x(x-9)(x+9)
Works every time.
OpenStudy (asnaseer):
as does:
lcm(a,b) = (a*b)/gcd(a,b)
OpenStudy (mertsj):
Absolutely however more complicated.
OpenStudy (asnaseer):
really?
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OpenStudy (mertsj):
Maybe it's whatever one is used to. We'll let the asker decide which he/she wishes to use.
OpenStudy (mertsj):
Choice is good.
OpenStudy (asnaseer):
agreed :)
OpenStudy (anonymous):
thanks guys :)
OpenStudy (mertsj):
yw
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