Question

Use Taylor's Inequality to estimate the accuracy of the approximation f ≈ Tn(x). |R_2(x)| ≤ M/3! |x − 9|^3 = ((1/648)/6) *(0.216) = ? See the progress that as been done so far down below in the attachment.

Answer 1

call @amistre64

Answer 2

thats alot of notation ....

Answer 3

http://www.youtube.com/watch?v=9LnCcAoEHG4

this guy is usually good at explaining these things; im gonna have to review it first to refresh my memory

Answer 4

Yeaaaah, it is. But i dont need anything else. I only need to solve this part and I can do the rest. Im supposed to round to 6 dcimals. I keep getting
0.000005" but the program says its wrong.

Answer 5

ok

Answer 6

For example: |R_2(x)| ≤ M/3! |x − 9|^3 = ((1/648)/6 ) * (0.008) = 0.000002 (rounded to six decimal places)

My issue is that I cant get the "0.000002" answer.

Answer 7

f ≈ Tn(x)

do we have an nth value by chance?

Answer 8

im still not sure what it is your looking for; do we want to find the nth term that makes us accurate to 6 decis?

Answer 9

f(x) = sqrt(x), a = 9, n = 2, 9 <= x <= 9.6

Im pretty much at the very end where I find the error, R_2.

Answer 10

Everything needed to solve it is he problem I typed at first

Answer 11

the*

Answer 12

i cant come up with an answer either ... having troubles concentrating on it :/

Answer 13

do you have a summation for the series representation?

Answer 14

lol!!! I can make an attachment. Its not THAT serious, but considering how I only need that part completed, i kinda dont wanna skip it. IF you still want to do it, just take your time.

Answer 15

hmm, i cant seem to open the file

Answer 16

Oh srry. Try now