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(p^-5)^3/7p^5
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\[\left( p^-5 \right)^3\over7p^5\]
\[p^{-15} \div 7p^{5} = 1\div 7p^{5} \times p^{-15} =\] now you add the p's exponent and you get 1/p^-10
thank you i completly for got how to do this
your welcome
wait thats not on the answer choice. hmm
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i think its 1 over7p^20
oh it is it 5-(-15) is 20
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