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Mathematics 11 Online
OpenStudy (anonymous):

In an experiment to study the growth of bacteria, a medical student measured5000 bacteria at time 0 and 8000 at time 10 minutes. Assuming that the number of bacteria grows exponentially, how many bacteria will be present after 30 minutes? (see attachment)

OpenStudy (anonymous):

OpenStudy (asnaseer):

for exponential growth, the umber of bacteria (b) would be related to the time in minutes (t) by:\[b=a*e^{kt}\]where 'a' and 'k' are some constants. you the two data points given to you to work out the value for 'a' and 'k'. then you should be able to work out the number of bacteria at 30 minutes.

OpenStudy (anonymous):

b(t) = a * e^(k * t) . Asnaseer is right

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