Question

integrate [(x)/(x^2 - 4)]dx

Answer 1

\[\int\limits_{}^{}(x/x^2 - 4)dx = ?\]

Answer 2

Looks like a u-substitution should do the trick:
Try: \(u = x^2 - 4\) ?

Answer 3

thanks, can you finish it please, I can't remember how

Answer 4

\( du = 2x\ dx \implies \frac{1}{2}du = x\ dx \)

\[ \int \frac{1/2\ du}{u} = \frac{1}{2} \int\frac{du}{u}\]

Makes sense?

Answer 5

you dont see 2 a derivative of x^2 so you need to put 2 up and then divide by 2 as you cant change the original part

so it will be 1/2 *ln(x^2 -4) +c

Answer 6

yes I got it thank you guys so much!

Answer 7

You're welcome! :)