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Mathematics 10 Online
OpenStudy (chrisplusian):

find the indefinite integral by u substitution

OpenStudy (chrisplusian):

\[\int\limits 1/(1+\sqrt{2x} )dx\]

OpenStudy (chrisplusian):

I have the solustions manual And amabout to show the part that confuses me.

OpenStudy (chrisplusian):

\[u=1+\sqrt{2x}\]

OpenStudy (chrisplusian):

\[du=1/\sqrt{2x}\]

OpenStudy (chrisplusian):

this much I got on my own, and it agrees with the solutions guide. then they show \[(u-1)du=dx\]

OpenStudy (chrisplusian):

this is where I am confused

OpenStudy (chrisplusian):

where does the (u-1) idea come from?

OpenStudy (anonymous):

\[du= \frac {dx}{\sqrt {2x}} \\ \sqrt{2x} du =dx\\ (u-1) du =dx\\ \] Since \[ u= 1 +\sqrt{2x}\\ u-1 =\sqrt{2x} \]

OpenStudy (chrisplusian):

thanks that is exactly what I needed

OpenStudy (anonymous):

With pleasure.

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