Question

Factor out the GCF from the polynomial 14y^5+8^3
I know the GCF of 14,5 is 2. I just don't know where to go from there help please.....

Answer 1

\[14y ^{5} + 8^{3}\] is this the problem?

Answer 2

yes

Answer 3

ok, this a little odd, not your normal factoing, start out by simplifing the 8 cubed

Answer 4

\[14y ^{5} + 512\]

Answer 5

then all you can factor out is a 2

Answer 6

\[2(7y ^{5} + 256)\]

Answer 7

so you would divide 14/2 and 8/2

Answer 8

\[8^{3}= 512\]

Answer 9

so you have 14/2 and 512/2

Answer 10

thanks

Answer 11

your GCF is 2 and when it is on the outside of the paranthases that means it has been "factored out" you could use the distributive property to get back to the origianl problem

Answer 12

distributive propety: a(b + c) = ab + ac

Answer 13

ok thanks