Question

how do i find the indefinite integral of 2x^9-6x^2+3/x^9

Answer 1

is that all over x^9?

Answer 2

yes

Answer 3

the i would suggest simplifying it first , like for the first term it would be 2x^9/x^9=2

Answer 4

ok

Answer 5

so, your good, or you still have some doubts

Answer 6

lagrange did good on this, so what is the question that remains?

Answer 7

what

Answer 8

recall the power rule for integrations\[\int x^ndx=\frac{1}{n+1}x^{n+1}\]
thats the only thing that would be needed to finish it up

Answer 9

i really dont know how to start the problem

Answer 10

Hint

Answer 11

1/(x^n)=x^(-n)

Answer 12

you start it with algebra .....

simplify the integrand

Answer 13

THe power rul for integration still applies, unless n=-1

Answer 14

so 2x^10/x^10?

Answer 15

Remember that you can seperate each term with the distributive property.

Answer 16

how

Answer 17

(2x^9-6x^2+3)/(x^9)
=(2x^9)/(x^9) -(6x^2)/(x^9) +3/(x^9)

Answer 18

Just pre algebra, my friend.