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anti derivative of the integral xe^x^2 dx
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\[\int\limits_{}^{} xe ^{x ^{2}} dx \] I have no idea how to do it with e in it.
Use the substitution \[u = x^2 \implies du = 2x dx \implies \frac{du}{2} = x dx\] Replace this in the integral, this gives: \[\frac{1}{2} \int\limits e^u du =\frac{1}{2}e^u + C = \frac{1}{2} e^{x^2}+C\]
where does the 1/2 come from thats in front of the integral?
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