A 10.-mL sample of hydrochloric acid neutralizes 15 mL of a 0.40 M solution of NaOH.what is the molarity of the hydrochloric acid?

Question

anonymous · Answer

$$15 ml HCl (\frac{.40 mole HCl}{1000 ml HCl}).006 mole HCl$$

anonymous · Answer

now we have to divid the moles of HCL by the liters on used

anonymous · Answer

i think we messed up because i need to find hcl molarity

anonymous · Answer

oh crap divid .006 by .010 i'm sorry

anonymous · Answer

$$\frac{.006}{.010}=.6 M HCl$$

anonymous · Answer

ooo ok yes i got it right then thankss

anonymous · Answer

could you help with one more if wouldn't mind?

anonymous · Answer

sure I can try

anonymous · Answer

oo its ok i got it ^_^

anonymous · Answer

welll wait

anonymous · Answer

write the electron dot diagram for the net ionic equation for a neutralization reaction.Be sure to include the charge on any ionic substance.

anonymous · Answer

Sorry I've never had to do a electron dot diagram so i'm afraid i wont be much help here. I would post it as a fresh question and see what you get

anonymous · Answer

oo ok thanks anyways