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Mathematics 19 Online
OpenStudy (anonymous):

Solve e^0.006x=29

OpenStudy (anonymous):

Is it \(\LARGE e^{0.006x} = 29 \)? Take the natural log on both sides, we are left with:\[0.006x = \ln{29} \implies x = \frac{\ln{29}}{0.006}\]Use a calculator now.

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