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find the general solution of the following differential equation: y dy/dx=sinx
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-cos x
what are the steps i dont just need the answer...
please...
I just learned like that. im not sure if there's any working for this. sorry.
Multiply both sides by dx to get: \[ ydy = sinx dx \]Integrate both sides: \[ \frac{y^2}{2} = -cos(x) + C_1 \implies y = \pm \sqrt{C - 2cosx}\]
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thxx
You are welcome :-)
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