Question

2/x dy/dx=1/y^2-3

Answer 1

Is it \[ \frac{2}{x} \frac{dy}{dx} = \frac{1}{y^2 - 3} \]?

Answer 2

i first dx both sides??

Answer 3

yes

Answer 4

Yeah, multiply both sides by xdx, then by (y^2 - 3). Integrate afterwards.

Answer 5

\[\frac{2}{x}\frac{dy}{dx}=\frac{1}{y^2-3}\]
\[\frac{2}{x}\frac{1}{dx}=\frac{1}{y^2-3}\frac{1}{dy}\]
\[\int\limits_{}^{}\frac{x}{2}dx=\int\limits_{}^{} y^2-3dy\]

Answer 6

@.Sam why do u ave 1/dy??

Answer 7

divide both sides by dy

Answer 8

ohhhh kk

Answer 9

after integration I get 2=y^3/3???

Answer 10

\[\int\limits_{}^{}\frac{x}{2}dx=\int\limits_{}^{} y^2-3dy\]
\[\frac{x^2}{4}=\frac{y^3}{3}-3y\]

Answer 11

Just integrate both sides separately

Answer 12

ok

Answer 13

thxxx:)