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e^x/5 - e^-x/5 how do you factor this out? i believe you take out e^-x/5, then...what next
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e^-x = 1/e^x
Now take LCM of the denominators and go ahead
oh ok thanks :)
Welcome :)
wait...u take out e^-x?
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not e^-x/5?
OK. \[\large \frac{e^x}{5} - \frac{1}{5e^x}= \frac{1}{5e^x}{(e^{2x} - 1)}\]
srry..it is e^ (x/5) ..forgot my brackets
e^ (x/5) - e (-x/5)
Apply same logic :D
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i took out e^(-x/5)
keep typing it wrong..e^ (x/5) - e ^(-x/5)
so i got e^ (-x/5) ( e^-1 - 1) is this right?
Not exactly \[\large {e^{x/5}} - \frac{1}{e^{x/5}}= \frac{1}{e^{x/5}}{(e^{2x/5} - 1)}\]
oh okok i get it thanks
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Welcome :D
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