given sin theta=4/5 with 90 dgreess less than or equal to thata less than or equal to 180 degress find exact value of : sin theta/2
\[\sin \theta=\ 4/5 \ with 90 degreess\] =\[180 degreess \] so its 1:2
huh?
ok
u=(2 cos pi/4)i + (2 sin pi/4)j, v = (cos 3pi/2)i + (sin 3pi/2)j find the angle theta .... If sin theta equals two third and zero degrees less than theta less than 90
ok tnaks
yes i need help
sin theta = 4/5 = 0.8 sin^-1 theta = 53.13010235 degrees sin (53.13010235/2) = 0.447213595
no but not indecimals
do it in a graph
I have the answer: sin (theta/2) = Square root (1/5) Do you want to know the method?
The length of the remaining side of the triangle is: square root of (5^2 - 4^2) = 3 Then use the formula for the sine of the half angle: sin (theta/2) = square root (((s - b)(s - c))/bc)) Where s = 1/2(a + b + c)
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