Question

integrate

Answer 1

what?

Answer 2

srry guys i am having a fight with eqn editor lols

Answer 3

\[\large \int\limits \frac{x-1}{(x-2)(x-3)}\]

Answer 4

at last

Answer 5

unintegrable! no dx :p

Answer 6

ya! lgba is right

Answer 7

oops i left that accidently during my fight

Answer 8

assume dx is present

Answer 9

cant get

Answer 10

??

Answer 11

\[\huge \int\limits \frac{(x-1)dx}{(x-2)(x-3)}\]

Answer 12

so you need to convert it into partial fractions ( thats how i did)

A/x-2 + B/x-3= x-1

A(x-3) + B(x-2) x-1

putting x=2 and x=3

we get

-1/x-2 dx + 2/x-3 dx

-lnx-2 + 1/2lnx-3 + C

Answer 13

using partial fractions we'll have (ill skip the fractions part)

x - 1 = Ax - 3A + Bx - 2B

-3A - 2B = -1

A + B = 1

-3A - 2B = -1
3A + 3B = 3

B = 2
A = -1

\(\Large \int \frac{-1}{x-2}dx + \int \frac{2}{x-3}dx\)

can you do that now?

Answer 14

ya

Answer 15

i did a mistake 2lnx-3 *

Answer 16

lgba rocks!!

Answer 17

whose ready for next one?

Answer 18

lgba :p