An interesting conjecture. Any even whole number more than or equal to 4 can be expressed as a sum of two prime numbers. For example: \[6=3+3\] \[32=19+13\] The list goes long but I am stopping right here.
how about 2000 :P
I don't really know it very long. It can be 991 + 1009, I think.
Yes, it is.
it is the property
what about 2?
1 + 1(because 1 is considered prime in some cases)
1 is not prime no
hmm...it is a matter of some debate
I know, but it does have the properties of a prime number.
it is not true 4 2
Let's leave 2 behind. More numbers?
@ParthKohli if you can solve this 5569652 it only proves that you have a calculator out there helping you :P lol
I guessed the 2000 one lol
since it is satiesfying aa even no it is property
one is an even whole number that cannot be expressed as a sum to two prime numbers
One is odd* @UnkleRhaukus
odd, hmm yeah i didn't really think about what this word meant haha
uncle pagla gaya h
isnt this Goldbach's Conjecture? its for even numbers greater than or equal to 4, so dont worry about 2.
parth qn change karo
For conventional purposes, 1 is not a prime, because we want integers to have a unique prime factorization. If 1 was considered a prime, then we would have:\[20=2^2\cdot 5=1\cdot 2^2\cdot 5=1^{100}\cdot 2^2\cdot 5=\cdots\]
is zero odd even or neither?
Even.
bhai joe see property of prime no see defination of prime
Why is 0 even?
because it is a multiple of 2
2*0 = 0;
3*0=0
Yes, this is Goldbach's
because it can be written as:\[0=2(0)\]any even number can be written as:\[n=2k\]any odd number can be written as:\[n=2k+1\]
O is even because it is divisible by 2.
oh i see
I changed it.
even comes after odd and before odd no -1 0 1
ok i'm convinced zero is even Can we use the Goldbach's Conjecture to find prime numbers?
We cannot.
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