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solve log base 8 of 64=x
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do you know log rules? ... which rule can be applied here? :)
\[\LARGE \log_a(b)=c\quad \Longrightarrow b=a^c\]
log base 8 of 64 = log base 8 of 8^2 applying the rule log base a of b = c = a^c you get 2.
\[\LARGE \log_{8}(64)=x\] \[\LARGE 64=8^x\] \[\LARGE 8^2=8^x\quad \iff 2=x\]
The logarithm of a number is the power to which the base must be raised to equal the number. Because 8^2=64, log(base 8)64 = 2
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x = xlog8(8) xlog8(8)=log8(64)=log8(8^2)=2log8(8) than x=2
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