Question

Evaluate Integral: 2sin(2x) from 0, pi/2

Answer 1

\[\int\limits_0^{\pi/2}2\sin(2x)\text d x\]
\[=2\times\{-\frac{\cos(2x)}{2}|_0^{\pi/2}\}\]

Answer 2

Did u use half or double angle formula??

Answer 3

Because sin(2x)= 2sin(x)cos(x)
Although, i know that antiderivative of sin is -cos.

Answer 4

um you might use the double angular formula if you were asked to integrate
2sin(x)cos(x) but in this question it would make the formula more complicated rater than more simple

Answer 5

i could have been more explicit with my integration

\[2\int\sin(2x)\text dx\]
let
2x=u
x=u/2
dx=du/2
\[2\int\sin(u)\frac{\text d u}{2}\]

Answer 6

U substitution will be the death of me, i swear. Thank you!! I get it now

Answer 7

i really struggled with t when i was first learning it by it is clear to me now,
do you have any more question./s

Answer 8

I have one on arc lengths = )

Answer 9

agh not my specialty

Answer 10

None of this stuff is my specialty,lol. Thanks alot!!!

Answer 11

Oh, considering how Calc 2 has many formulas isthere any special way u have memorized them??

Answer 12

well i dont remember many of trig formulas but i can usually look them up or work them out if i have to