A 588 N mother sits on one side of a seesaw, 2.20 m from the pivot. One of her two children sits
2.00 m from the pivot on the other side of the seesaw. If the force of gravity on her is 256 N, where
must the other child sit to balance the seesaw if the force of gravity on him is 412 N?

Question

A 588 N mother sits on one side of a seesaw, 2.20 m from the pivot. One of her two children sits
2.00 m from the pivot on the other side of the seesaw. If the force of gravity on her is 256 N, where
must the other child sit to balance the seesaw if the force of gravity on him is 412 N?

anonymous · Answer

i have the answer (1.9m) but i dont know how to get it

anonymous · Answer

The see-saw is balanced when there is no resultant torque on either side. If the mother created torque in the anti-clockwise direction, the children, being on the opposite side, create a clockwise torque. Take the distance of the second child from pivot as x. Equate torques and solve for x.

ujjwal · Answer

weight of mother * distance of mother from pivot = weight of first child * its distance from pivot + weight of second child * its distance from pivot

mos1635 · Answer

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