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Please help me! If y'= x(1 + y) and y > -1 , then y = Please see the attachment (Thank You)
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Seperate the variables, so everything with y and y' on one side, x on the other.
Not sure what you mean. you start with y'= x(1 + y), then you divide or multiply both sides by the same things until you've separated the variables. I'd divide both sides by 1+y
This is just the first step, so now we have: \[\frac{y'}{1+y}=x\]
The variables are now seperated. Now the following holds: \[\int\frac{1}{1+y}dy=\int x dx\]
Can you compute both sides?
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1/2 x^2 + C
Do you agree with that? What's the left side?
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