Question

Help! for the equation x^2+3x + j=0,find the values of j, the equation has two real numbers

Answer 1

you have the quadratic equation there

to have two real SOLUTIONS

it should be
\[\LARGE \Delta=b^2-4ac\]
\[\LARGE \Delta>0\]
so when \(\Delta>0\) there are two solutions so you need to substitute
\[\LARGE b^2-4ac>0\]
but remember instead of "c" you have "j"
so...
\[\LARGE b^2-4aj>0\]
\[\LARGE 3^2-4j>0\]
\[\LARGE -4j>-9 \]
solve for "j" and you'll have the answer.

Answer 2

Im still confused

Answer 3

have you ever solved quadratic equations?

Answer 4

not really

Answer 5

then I think you're not capable for these kind of problems... Google quadratic equations and do some practice, once you've learnt those you'll not get confused when you'll review this question...

Answer 6

Im just getting startedon these ,thats why i need some help

Answer 7

do I multiply these so the -4 *-9