Question

Please help me!

Suppose an experimental population of amoeba increases according to the law of exponential growth. There were 100 amoeba after the second day of the experiment and 300 amoeba after the fourth day. Approximately how many amoeba were in the original sample?

Please see the attachment: (Thank You)

Answer 1

Ok, you will need to solve a system here. The equation will be \( y = P_o e^{kt} \) with Po being the initial population and t in days

Answer 2

Then use both informations to get that 100 = Poe^(2k) and 300 = Poe^(4k). Solve for k and for Po :-)

Answer 3

log both sides, you will get
ln(100) = ln(Po) + 2k
ln(300) = ln(Po) + 4k
I will do the arithmetic in a bit to check my answer.

Answer 4

Yup, got A also