Please help me!

The velocity of a particle on the x-axis is given by the differential equation and the particle is at x = 5, when t = 1. The position of the particle as a function of time is x(t) =

Please see the attachment (Thank You)

Question

Please help me!

The velocity of a particle on the x-axis is given by the differential equation  and the particle is at x = 5, when t = 1. The position of the particle as a function of time is x(t) =

Please see the attachment (Thank You)

anonymous · Answer

attachment

anonymous · Answer

quadratic formula

anonymous · Answer

Separate the variables, integrate both sides with respect to dx and dt, you should get
x = (-t^(3/2))/2 + C (remember the power rule for integral? x^n = (x^(n+1))/(n+1)

anonymous · Answer

So the answer would be "B". Am i right?

anonymous · Answer

Careful. It should have only $ -\frac{1}{2} t^{\frac{3}{2}} + C $

anonymous · Answer

If x = 5 when t = 1, C is?

anonymous · Answer

C is the answer? 1 MINUTE left!!!!

anonymous · Answer

D, man. There is only one with -1/2 t^3/2 :P

anonymous · Answer

THank you!!!!!!!!!!!!!!!

anonymous · Answer

No problem :-)