pllz can anyone help me with this :
A 25-turn square coil with a mass of 0.320 kg and a side of 0.210 m is hinged along a horizontal side, carries a 6.00-A current and is placed in a vertical magnetic field pointing down and having a magnitude of 4.00 mT. Determine the angle that the plane of the coil makes with the vertical when the coil is in equilibrium. Use g = 9.81 m/s

Question

pllz can anyone help me with this :
A 25-turn square coil with a mass of 0.320 kg and a side of 0.210 m is hinged along a horizontal side, carries a 6.00-A current and is placed in a vertical magnetic field pointing down and having a magnitude of 4.00 mT. Determine the angle that the plane of the coil makes with the vertical when the coil is in equilibrium. Use g = 9.81 m/s

anonymous · Answer

You must use torque vectors acting on the coil. Torque due to magnetic force is  equal to the net torque due to gravitational force. Solving this equation you will get the angle. The answer according to my calculations is 2.3 degrees.