Question

Simplify: x^2-16/ 4x divided by (x-4)

Answer 1

We know that \[a^2-b^2 = (a-b)(a+b)\]So x^2 - 16 would be \[x^2 - 16 = (x-4)(x+4)\]

Answer 2

as @zepp said:
\[\LARGE \frac{(x-4)(x+4)}{x-4}=\frac{\cancel{(x-4)}(x+4)}{\cancel{x-4}}\]

Answer 3

^ There, I suck at typing in LaTeX :(

Answer 4

Wait, @Kreshnik, you forgot the 4x

Answer 5

\[\frac{(x-4)(x+4)}{4x(x-4)}\]\[\frac{(x+4)}{4x}\]

Answer 6

auff.. LOL

I guess I didn't read the question properly
\[\LARGE \left[\frac{(x-4)(x+4)}{4x}\right] \div (x-4)=\]
\[\LARGE \frac{(x-4)(x+4)}{4x} \times \frac{1}{(x-4)}=\]
\[\LARGE \frac{\cancel{(x-4)}(x+4)}{4x} \times \frac{1}{\cancel{(x-4)}}=\]
\[\LARGE \frac{x+4}{4x }\]