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simplify complex fractions:
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\[x ^{-2}-9y ^{-2} \over 5y-15x\]
\[\frac{\frac{1}{x^2}-\frac{9}{y^2}}{5y-12x}\] is a start. then perhaps multiply top and bottom by \(x^2y^2\) to clear the fraction
thats 15 not12
you should get \[\frac{y^2-9x^2}{x^2y^2(5y-15x)}\] then factor and cancel a bit
\[\frac{(y-3x)(y+3x)}{5x^2y^2(y-3x)}\] one step left
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um cancel out y-3x
yes
thank you so much
yw
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