Question

Solve the following equation. One point is given for showing steps and one point given for the correct solution. x/x+3+2/5=0

Answer 1

We have
\[\frac{x}{x+3}+\frac{2}{5}=0\]
\[\text{We need to find x}\]
Are you here @Kaupkel?

Answer 2

Yepp I'm here

Answer 3

Let's subtract both sides by 2/5, we get

\[\frac{x}{x+3}+\frac{2}{5}-\frac{2}{5}=0-\frac{2}{5}\]
Now we get
\[\frac{x}{x+3}=\frac{-2}{5}\]Let's multiply both sides by \(5( x+3)\)
We have
\[\frac{x}{x+3}\times 5(x+3)=\frac{-2}{5} \times 5(x+3)\]
Now let's cancel the common terms, from both sides
\[\frac{x}{\cancel{x+3}}\times 5\cancel{(x+3)}=\frac{-2}{\cancel5} \times \cancel 5(x+3)\]
We get
\[5x=-2(x+3)\]
Now Let's simplify the right side
\[5x=-2x-6\]
Add 2x to both sides
\[5x+2x=-2x-6+2x\]
We get
\[7x=-6\]
Divide both sides by 7
we get
\[x=\frac{-6}{7}\]
Do you understand this?