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The maximum value of f(x) = -e^x + x is:
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A) 0 B) 2 C) ln 2 D) -1 E) 1
Diff it and put equal to 0
ok
f'(x) = -e^x
What about the other bit?
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+ 1
f'(x) = -e^x + 1
So put it equal to O
0 = -e^x + 1
x=?
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the e is euler's constant right?
Euler's constant is something else, sometimes it's called Euler's number
Anyway, u got your answer, right?
nope. can you take it from here?
e is the number 2.7... etc. Subtract 1 from the above equation, you will get: -1 = -e^x => e^x = 1 Take the natural log on both sides: x = ln(1) = 0 :-)
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So now sub that in your original to get the max value.
-1 yay! thanks you guys.
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