Question

Solve log3x+log9=0. round to nearest hundredth if necessary
a..33
b..04
c.3
d.27

Answer 1

\[\log(3x)+\log(9)=0 ?\]

Answer 2

how do i solve

Answer 3

If that is the right expression use that property I mentioned earlier

log(a)+log(b)=log(ab)

-----------
log(3x)+log(9)=log(3x*9)=log(27x)

So you need to solve the following for x:
log(27x)=0

Answer 4

so multiply log(3*9)

Answer 5

Yes but you missed the x inside there

log(27x)=0
when x= what?

Answer 6

I assume the base is 10

so we have
\[\log_{10}(27x)=0\]
Do you know how to solve for x?

do 10^ on both sides

Answer 7

3

Answer 8

\[10^{\log _{10}(27x)}=10^0\]
\[27x=1\]
Can you finish this ?

Answer 9

yea

Answer 10

cool! :)