Question

Please help me... 2ln(x)+ln(x)^2=3

Answer 1

I've gotten to this step lnx^2+lnx^2=3

Answer 2

So you can think of this as a quadratic equation where you are solving for ln(x).
Let z = ln(x)
\[z^2 + 2z -3 = 0\]

Answer 3

\[(z+3)*(z-1) = 0\]
z = -3 or 1
ln(x) = -3 or 1
\[x = e^{-3} ,e^{1}\]

Answer 4

ln(x^2) isn't the same as (ln(x))^2

Answer 5

The equation editor is very useful in this kind of case. Do you know which one you mean?
\[\ln{x^{2}}\] or
\[(\ln{x})^{2}\]

Answer 6

@amy_renae1994
Please tell us how you meant to post the problem. Use draw or equation editor

Answer 7

\[2\ln x+\ln ^{2}=3\]

Answer 8

what happened to the second x? can't have ln^2

Answer 9

I'm sorry i meant to put it in there..

Answer 10

http://www.wolframalpha.com/input/?i=solve+2ln%28x%29%2Bln%5E2%28x%29%3D3

Answer 11

Omg, I love you right now. I tried using wolframalpha earlier. Thanks so very much

Answer 12

@Valpey I stand corrected
@amy_renae1994 I erased my work so I do not confuse you

Answer 13

Bah, I totally forgot that the notation was:
\[\ln^{2}{x}\]