What is the period of the function 2cos(3πx)?

Question

anonymous · Answer

period in this case is equal to:

Period= $$2pi/ 3pi = 2/3$$

anonymous · Answer

$$\frac{2\pi}{b}$$ for period of $\sin(bx)$ or $\cos(bx)$

anonymous · Answer

gd job satellite

anonymous · Answer

The factor 2 makes the curve bigger but doesn't affect the period, so just look at cos(3pi x).  What is this value when x=0?  When will the cosine again be that value?

kropot72 · Answer

The angular frequency is 2*pi*f
2*pi*f = 3*pi*x from which f = (3/2)*x
Period is 1/f = 2/(3*x)

anonymous · Answer

hey kropot72 what is the x at the bottom for?

kropot72 · Answer

Because when the reciprocal of the expression was taken that's where it goes. If you want it at the top:
Period T = (2*x^-1)/3

anonymous · Answer

that is not what I mean, look at this and check where it talks about the period, you do not need the x at all. http://science.kennesaw.edu/~plaval/applets/TrigCos.html

kropot72 · Answer

At your link the period is a function of the variable k. Note that k is the denominator. In the question here the variable has been named x.